(x^2+3x-1)-(2x+1)=x^2-5

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Solution for (x^2+3x-1)-(2x+1)=x^2-5 equation:


Simplifying
(x2 + 3x + -1) + -1(2x + 1) = x2 + -5

Reorder the terms:
(-1 + 3x + x2) + -1(2x + 1) = x2 + -5

Remove parenthesis around (-1 + 3x + x2)
-1 + 3x + x2 + -1(2x + 1) = x2 + -5

Reorder the terms:
-1 + 3x + x2 + -1(1 + 2x) = x2 + -5
-1 + 3x + x2 + (1 * -1 + 2x * -1) = x2 + -5
-1 + 3x + x2 + (-1 + -2x) = x2 + -5

Reorder the terms:
-1 + -1 + 3x + -2x + x2 = x2 + -5

Combine like terms: -1 + -1 = -2
-2 + 3x + -2x + x2 = x2 + -5

Combine like terms: 3x + -2x = 1x
-2 + 1x + x2 = x2 + -5

Reorder the terms:
-2 + 1x + x2 = -5 + x2

Add '-1x2' to each side of the equation.
-2 + 1x + x2 + -1x2 = -5 + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
-2 + 1x + 0 = -5 + x2 + -1x2
-2 + 1x = -5 + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
-2 + 1x = -5 + 0
-2 + 1x = -5

Solving
-2 + 1x = -5

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + 1x = -5 + 2

Combine like terms: -2 + 2 = 0
0 + 1x = -5 + 2
1x = -5 + 2

Combine like terms: -5 + 2 = -3
1x = -3

Divide each side by '1'.
x = -3

Simplifying
x = -3

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